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Diffstat (limited to 'tutorial/variable.md')
| -rw-r--r-- | tutorial/variable.md | 10 |
1 files changed, 8 insertions, 2 deletions
diff --git a/tutorial/variable.md b/tutorial/variable.md index 3e3f7467..71f28789 100644 --- a/tutorial/variable.md +++ b/tutorial/variable.md @@ -201,12 +201,18 @@ But this changes the value of `a` to a completely unrelated value. What if I wan a ∾˜↩ 0‿1 -But what about functions with only one argument? The syntax isn't the best, but at least it's possible. There still needs to be a value on the right side of the assignment even if it'll be ignored; I use the null character `@` for this. Then to turn a function that takes one argument into one that takes two, we can compose it with a function that takes two arguments and returns one of them. The left one, since the variable to modify is on the left hand side. Perhaps… Left? (`⊣`)? +But what about functions with only one argument? It's possible to do this using a dummy right argument such as the null character, `@`. To turn a function that takes one argument into one that takes two, we can compose it with a function that takes two arguments and returns one of them. The left one, since the variable to modify is on the left hand side. Perhaps… Left? (`⊣`)? "abcd" ⌽∘⊣ "wxyz" a ⌽∘⊣↩ @ +But fortunately, there's a simpler syntax as well: write your one-argument function before `↩` with no right hand side. Bit of a Yoda vibe: "`a` reversed is". + + a ⌽↩ + + a 4⊸-↩ # And back again + Notice that there's no need for parentheses: modifiers bind more strongly than the assignment character. Now what if we want to decrease the last two elements of `a`? That is, we want to compute the following array while storing it in `a`. -⟜4⌾(¯2⊸↑) a @@ -215,4 +221,4 @@ Notice that there's no need for parentheses: modifiers bind more strongly than t The code to do this looks the same as what we did with Reverse (`⌽`). Again we don't have to parenthesize the function, because modifiers associate from left to right, so Under (`⌾`) binds to its operands before Compose (`∘`) does. - a -⟜4⌾(¯2⊸↑)∘⊣↩ @ + a -⟜4⌾(¯2⊸↑)↩ |